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x^2+0.34x=0.06
We move all terms to the left:
x^2+0.34x-(0.06)=0
We add all the numbers together, and all the variables
x^2+0.34x-0.06=0
a = 1; b = 0.34; c = -0.06;
Δ = b2-4ac
Δ = 0.342-4·1·(-0.06)
Δ = 0.3556
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.34)-\sqrt{0.3556}}{2*1}=\frac{-0.34-\sqrt{0.3556}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.34)+\sqrt{0.3556}}{2*1}=\frac{-0.34+\sqrt{0.3556}}{2} $
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